Question

If 0.86 mole of MnO₂and 44.0 g of HCl react, how many grams of Cl₂will be produced?

MnO₂+ 4HCl → MnCl₂+ Cl₂+ 2H₂O g

Answer 1

ANS. We can see from the given reaction that the reactants react in mole ratio of 1:4. So with 1 mole of MnO₂ 4 moles of HCl will react and form 1 mole of Cl₂ . Now we have to calculate moles of HCl and see if it is the limiting reagent or not.

Molar mass of HCl = 36.5

Amount given =   44gm

Moles = 44/36.5

= 1.20

Moles of MnO₂ given = 0.98

Since both are not in ratio of 1:4 HCl is the limiting reagent and hence the formation of moles of Cl₂ will be 1/4 th of moles of HCl given.

So moles of Cl₂ that will form =0.3 moles

Molar mass of Cl₂ = 71

Amount of Cl₂ formed in gm = 0.3*71

= 21.3 gms