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An aliquot of 25.0 mL of water is used to dissolve 0.200g Na2CO3is titrated with a...

An aliquot of 25.0 mL of water is used to dissolve 0.200g Na2CO3is titrated with a 0.10 M HCl solution. How many mL of a HCl solution would be required to reach the first equivalence point?

With the same solution in question 1, how many total mL of the 0.10 M HCl solution are required to completely neutralize the soda ash solution? [hint: it would be helpful to write a balanced equation for this neutralization reaction].

A sample of ore containing soda ash (Na2CO3) is analyzed by titrating with 0.100 M HCl. If a 1.008 g sample requires 23.5 mL of the 0.100 M HCl solution for titration to the second equivalence point, what percentage of the ore is soda ash?

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