Question

Let a population consist of the values 7 cigarettes,8 cigarettes, and 22 cigarettes smoked in a...

Let a population consist of the values 7 cigarettes,8 cigarettes, and 22 cigarettes smoked in a day. Show that when samples of size 2 are randomly selected with​ replacement, the samples have mean absolute deviations that do not center about the value of the mean absolute deviation of the population. What does this indicate about a sample mean absolute deviation being used as an estimator of the mean absolute deviation of a​ population?

Calculate the mean absolute deviation for each possible sample of size 2 from the population.

Sample

Mean Absolute Deviation

​{7,7​}

nothing

​{7,8​}

nothing

​{7,22​}

nothing

​{8,7​}

nothing

​{8 ,8​}

nothing

​{8 ,22​}

nothing

​{22,7​}

nothing

​{22,8​}

nothing

​{22 ,22​}

nothing

​(Type integers or decimals rounded to one decimal place as​ needed.)

0 0
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Answer #1
mean absolute deviation
7,7 0
7,8 0.5
7,22 7.5
8,7 0.5
8,8 0
8,22 7
22,7 7.5
22,8 7
22,22 0

mean absolute deviation of the population =6.44 which is not equal to mean of sampling distribution of mean absolute deviation 3.33

therefore it is not an unbiased estimator of population mean absolute deviation

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