Suppose a wave function were assumed to be given by ψ = A from x = a to x = b, ψ = 0 elsewhere. Normalization yields what value for A?
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1 |
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b - a |
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(b - a)-1 |
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(b - a)-1/2 |
Wavefunction = A
Normalisation

dx = 1
[
b-a] = 1
=1/(b-a)
Taking square root on both sides
A= 1/(b-a)^1/2
A=( b-a)^-1/2
Last option is correct
Suppose a wave function were assumed to be given by ψ = A from x =...
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