Question

Consider an aqueous solution of calcium nitrate added to an aqueous solution of sodium phosphate. What is the formula of the solid formed in the reaction?

You mix 55 mL of 1.00 M silver nitrate with 25 mL of 0.55 M sodium chloride. What mass of silver chloride should you form?

2.0 g

2.2 g

4.3

3.9 g

None of these choices are correct.

In the balanced molecular equation for the neutralization of sodium hydroxide with sulfuric acid, the products are:

Na₂S + 2H₂O

NaSO₄ + H₂O

NaSO₃ + 2H₂O

Na₂SO₄ + 2H₂O

2NaSO₄ + H₂O

Answer 1

1) calcium nitrate on reaction with sodium phosphate produced sodium nitrate along with a precipitate of calcium phosphate with a formula Ca₃(PO4)₂

2)We first calculate the number of moles of silver nitrate and sodium chloride provided:

AgNO3 :(55/1000) * 1 = 0.055 moles

NaCl : (25/1000) * 0.55 = 0.01375 moles

The reaction proceeds as follows :

AgNO3 + NaCl -> AgCl + NaNO3

1 mole AgNO3 requires 1 moles NaCl to produce 1 mole of silver chloride.

Therefore NaCl acts as the limiting reagent since we only have 0.01375 miles of nacl for 0.055 moles of agno3

Therefore , moles of AgCl formed for 0.01375 moles of NaCl : 0.01375 moles

Weight of one mole of AgCl = 143 g

Weight of 0.01375 moles of AgCl : 0.01375 * 143 = 1.96 g

Nearest answer : 2.0 g

3)given reaction :

2NaOH + H2SO4 -> Na2SO4 + 2H2O