Question

A researcher wants to know what percentage of students at two different universities study for more...

A researcher wants to know what percentage of students at two different universities study for more than one hour per night. He takes a simple random sample of 100 students from each school and finds that 40% of students at school 1 study for more than one hour per night and 35% of students at school 2 study for more than one hour per night.

Construct a 95% confidence interval for the difference between the proportion of students who study for more than one hour per night at these two universities

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
A researcher wants to know what percentage of students at two different universities study for more...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A researcher surveys middle-school students on their study habits. She finds that in a random sample...

    A researcher surveys middle-school students on their study habits. She finds that in a random sample of 28 middle-school students, the mean amount of time that they spend working on the computer each night is 2.4 hours with a standard deviation of 0.92 hours. She uses the sample statistics to compute a 95% confidence interval for the population mean - the the mean amount of time that all middle-school students spend working on the computer each night. What is the...

  • A researcher surveys middle-school students on their study habits. She finds that in a random sample...

    A researcher surveys middle-school students on their study habits. She finds that in a random sample of 28 middle-school students, the mean amount of time that they spend working on the computer each night is 2.4 hours with a standard deviation of 0.92 hours. She uses the sample statistics to compute a 95% confidence interval for the population mean - the the mean amount of time that all middle-school students spend working on the computer each night. What is the...

  • The student council at greenwood high school (a large urban high school) wants to know what...

    The student council at greenwood high school (a large urban high school) wants to know what proportion of the studen body favors banning plastic water bottles from the school buildings and grounds. A simple random sample of 152 students finds that 85 support banning plastic bottles. a) Construct and interpret a 95% confidence interval for the proportion of students at Greenwood High School who support banning plastic water bottles. b)The student council will ban the bottles if they are convinced...

  • A researcher wants to use a confidence interval to estimate the proportion of college students in...

    A researcher wants to use a confidence interval to estimate the proportion of college students in his state who plan to vote in the 2020 presidential election. He plans to randomly sample 120 college students, and plans to construct a 95% or 99% confidence interval. Which of these confidence intervals will be wider, and why? Group of answer choices _99%. As the level of confidence increases, the width of the confidence interval increases. _95%. As the level of confidence decreases,...

  • Nintendo wants to know whether MarioKart is popular amongst students who have access to gaming devices....

    Nintendo wants to know whether MarioKart is popular amongst students who have access to gaming devices. A manager collected a random sample of 1,000 students with access to gaming devices. He reports that 35% of students in the sample like MarioKart. He correctly reports that the margin of error for a confidence interval estimate for the proportion of students (with access to gaming devices) who like MarioKart is 3 percentage points at a 95% confidence level. i) State the confidence...

  • A researcher wants to determine whether high school students who attend an SAT preparation course score...

    A researcher wants to determine whether high school students who attend an SAT preparation course score significantly different on the SAT than students who do not attend the preparation course. For those who do not attend the course, the population mean is 1050 (? = 1050). The 16 students who attend the preparation course average 1200on the SAT, with a sample standard deviation of 100. On the basis of these data, can the researcher conclude that the preparation course has...

  • A researcher wants to determine what percentage of the population skips breakfast. A study was done...

    A researcher wants to determine what percentage of the population skips breakfast. A study was done several years ago that found 39% of people do not eat breakfast. How large of a sample would the researcher need if he wants to be at a 95% confidence level as well as a margin of error of 2%?

  • s moking in high school students. She A researcher wants to know if an experimental"Smoke Out"...

    s moking in high school students. She A researcher wants to know if an experimental"Smoke Out" class for girls compted to a regular girls' health class at another school will stificantly also wants to know whether student grade level 19-12) makes a difference. ch accordingly Grade in school Location of the school A. A constant B. Dependent variable: C. Extraneous variable D. Active independent variable Attribute independent variable F. Study population Amount of smoking Highschool students

  • Clarence wants to estimate the percentage of students who live more than three miles from the...

    Clarence wants to estimate the percentage of students who live more than three miles from the school. He wants to create a 98% confidence interval which has an error bound of at most 4%. How many students should be polled to create the confidence interval? z0.10 z0.05 z0.025 z0.01 z0.005 1.282 1.645 1.960 2.326 2.576 Use the table of values above. Provide your answer below:

  • Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying...

    Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 15​ students, she finds 2 who eat cauliflower. Obtain and interpret a 95​% confidence interval for the proportion of students who eat cauliflower on​ Jane's campus using Agresti and​ Coull's method. Construct and interpret the 95​% confidence interval. One is 95% confident that the poplulation of students who eat cauliflower on janes campus is between___and ____? *Use the corrent z store interval for 95%...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT