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The specific heat of ethanol is 0.58 cal/g·°C, and the density of ethanol is 0.79 g/mL....

The specific heat of ethanol is 0.58 cal/g·°C, and the density of ethanol is 0.79 g/mL.

(Enter your answer to two significant figures.)

How much heat must you remove from 66 pounds of ethanol to cool it from 70°F to 40°F?

Heat =  kcal

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Answer #1

Ans :

Mass of ethanol = 66 pounds = 29937.1 g

heat = mass x specific heat x change in temperature

initial temperature = 70oF = 21.1111oC

final temperature = 40oF = 4.44444oC

change in temperature = 21.1111oC - 4.44444oC = 16.6666oC

putting values :

= 29937.1 g x 0.58 cal/goC x 16.6666oC

= 289391.8 cal

heat in kcal = 289391.8 / 1000 kcal

= 290 kcal

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