Question

You will write a program that will read a number from the user. You may use either the Scanner of the BufferedReader. You will verify that the number is indeed a number (use try/catch), if it is not a number you will end the program. If it is a number then you will verify that is a positive integer in the range from 1 to 9 (inclusive). If the number is not in range you will end the program. If the number is in range you will print the number itself as many times as the number. You MUST use a looping structure, either for, while or do loops. Example: If the user enters the number 6, the output of your program should be.

666666

Answer 1

/* Here is your required code*/

import java.util.Scanner;
public class Main
{
   public static void main(String[] args) {
   Scanner sc=new Scanner(System.in);
   System.out.print("Enter number in range(1-9)");
   String n=sc.next();
   try{
   Integer.parseInt(n);
   int m=Integer.parseInt(n);
   if(m>0&&m<10)
   {
   for(int i=0;i<m;i++)
   System.out.print(m);
   }
   else
   System.out.print("Number not in range(1-9)");
   }
   catch(NumberFormatException ex){
       System.out.println("Input is not number");
   }
   }
}