Question

C++. What is happening in this code?

I'm having a bit of difficulty understanding some lines of code due to pointers. Please refer to the comments and correct me on what is going on in the code. Thank you.

Practice code:

int ted = 25;
//int andy;
cout << ted << endl; //Prints 25
cout << endl;

  
int*andy = &ted;
cout << ted << endl; //Prints 25
cout << endl;

cout << &ted << endl; //Prints address of ted
cout << endl;

cout << andy << endl; //Prints same address
cout << endl;

cout << *andy << endl; //Prints 25
cout << endl;

cout << &andy << endl; //Prints the address of int*andy
cout << endl;

cout << ted << endl;
cout << endl;

//cout << *ted << endl; //Question: Why won't this run?
//cout << endl;

int* fred = andy; //Question: What is happening here?
cout << andy << endl;
cout << endl;

cout << fred << endl; //Question: What is happening here?
cout << endl;

cout << *fred << endl; //Prints 25
cout << endl;

cout << &fred << endl; //Question: What is happening here?
cout << endl;

cout << &andy << endl; //Question: What is happening here?
cout << endl;

cout << *andy << endl; //Prints 25
cout << endl;

Answer 1

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please do reachout to me if you need more explanation, as I can understand that the concept of pointers take some time to understand :)

* is read as value at the address of

& gives the address of the variable

so *Fred means the value at the address of Fred, means it will take the value of Fred goes to the address where the address value = fred value and returns the value at that address

//cout << *ted << endl; //Question: Why won't this run?
//cout << endl;
// because ted is a variable and * means value at the
// address of red so which means you are finding the
// value at the address of 25, since we dont know
// what is there at the address of 25 compiler might give
//error or some random value