The equilibrium constant for the reaction: 2 AB(g) ⇔ A2(g) + B2(g) is Kp = 0.363 at...

Question

Question

The equilibrium constant for the reaction:

2 AB(g) ⇔ A₂(g) + B₂(g)

is K_p = 0.363 at 873 K. What is K_p at 873 K for the reaction:

4 A₂(g) + 4 B₂(g) ⇔ 8 AB(g)

science chemistry

Answer 1

Answer #1

Answer 2

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