1. The incidence of Miller syndrome, a rare, recessive Mendelian disease, is 0.32%. Assuming that the population is in Hardy-Weinberg equilibrium for the gene that causes this disease, calculate the percent of the population that is a carrier for Miller syndrome.
2. Due to assortive mating, the frequency of genotypes is AA: 46%; Aa: 0%; aa: 54%
a.Calculate p and q for this population.
b.What is the expected genotype frequencies in Hardy-Weinberg equilibriumc. Assume that assortive mating ceases. How many generations will it take for the genotype frequencies to relax to Hardy-Weinberg equilibrium? Hint: calculate the expectant genotype frequencies in the next generation by identifying the possible mating classes (e.g. AA x AA), their probabilities, and their possible offspring. Sum these up and compare to Hardy-Weinberg equilibrium.
1.
Normal = MM, Mm
Affected = mm
mm = 0.32%
m = √0.32 = 0.5656
M = 1 - m = 1 - 0.5656 = 0.4344
Frequency of heterozygotes = Mm = 2 × 0.5656 × 0.4344 = 0.4913
Percentage of heterozygotes (carriers) = 0.4913 × 100 = 49.13%
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1. The incidence of Miller syndrome, a rare, recessive Mendelian disease, is 0.32%. Assuming that the...
In the figure, p is the frequency of allele A, and is the frequency of allele a in a diploid population. Assuming no differences in fitness, pand should also be the frequencies of A gametes and a gametes produced by the adults. The A and a gametes combine during fertilization to produce diploid zygotes. If mating is random and the population is large, the proportion of offspring with each of three genotypes (AA, Aa, and aa) can be predicted using...
The answers are shown, but how do you get the answer to
part IV ONLY. Please show all work and explain
NAME: 13. Consider a species that is divided into two subpopuiations that are each individually in Hardy- Weinberg equilibrium with the following genotype frequencies FIAA) FIAa) Flaa) 049 0.42 0.09 0.04 0.32 0.64 i. Assuming that the two subpopulations are of equa! size, calculate the overall genotype frequencies in the global population. Use your answers to complete the blanks...
1. Fixation of Dominant Alleles Start with a population that has a gene with two alleles (A and a) with classical Mendelian dominance that are at equal frequency (p0.5. q 0.5). Assume this first generation is at hardy Weinberg equilibrium. Calculate the genotype frequencies AA- a. Aa b. Now assume some environmental change that makes the recessive phenotype completely unfit (fitness- 0). Calculate the allele frequencies and genotype frequencies in the second generation. (Hint: Your calculations might be easier if...
Chi square problem need help please show work of how they
solved for the chi square value, the correct answer is in
red.
**On this page and the next two, report all* calculated non-integer values to the nearest 0.01** 18. x2. As you learned in one or more of your introductory biology courses, the frequencies of the genotypes in a population at "Hardy-Weinberg" equilibrium can be predicted from the frequencies of the individual alleles "A" and "a' at the locus...
4) Cystic fibrosis is a human disease caused by an autosomal recessive mutation. About 1 in 22 people in the human population are heterozygous carriers and have no symptoms of the disease. A woman who has a brother with CF marries a man who has no history of CF in his family a) What are the possible genotypes of the woman? b) What is the most likely genotype of the man? c) What is the percentage of offspring that would...
Mendelian Genetics The gene involved in the disease Sickle Cell Anemia (SCA) is on human chromosome 11. Allele “A” is the normal form of the gene and codes for a part of the protein complex called hemoglobin. Hemoglobin is required for your blood cells to carry oxygen. Allele “a” is an abnormal form of the gene. The hemoglobin protein made from the “a” allele is defective. Red blood cells containing the defective protein are very fragile. This disease is recessive–meaning...
1. In Eastern Gray Squirrels, the allele for Greay coat color (G) is dominant to the allele for black coat color (g). In a population of 200 squirrels, there are 18 black squirrels. The population is in Hardy-Weinberg equilibrium. a. What is the genotype of the 18 black squirrels? b. What is the frequency of the bb genotype in this population? c. What is the frequency of the b allele? d. What is the frequency of the B allele? e....
Which of the following statements regarding the Hardy-Weinberg Equation is TRUE? Answers: It can only be used when allele and genotype frequencies remain constant across generations in a population It can only be used when allele and genotype frequencies change across generations in a population It has no assumptions It mathematically shows how recessive alleles in a population decrease over time It reveals when allele frequencies change over time in a population Assuming Hardy-Weinberg Equilibrium, what percentage of individuals in...
5. Fur colour in mice is a single gene trait controled by two alleles. In a population of 75 mice, 21 are homozygous dominant, 37 are heterozygous dominant, and 17 are homozygous recessive. What is the frequency of the dominant allele in the population? Show all work and record your answer as a value between O and 1 rounded to two decimal places 6. The Hardy-Weinberg principle states that allele and genotype frequencies remain constant from one generation to the...
i wouldnt mind if someone could check my work on the first
page. but whats confusing me is section B. it starts on the bottom
of the first page and carries onto the second page.
A. Estimation of allele frequency for a specific trait Fill in the tables below for taster and allele frequencies in your class section. Taster/Non-taster Frequency=Genotype frequency (1 pt) # of students #Tasters Frequency of # Non-tasters in Lab Section Tasters (p+2pg) 16 1 = 5125...