MIPS QUESTION
This project will entail reading in a string of 4 characters into a variable (Beware if Endians). You must then take each individual character and load them into separate register ($t0-$t3). They then MUST be placed on the stack and then “popped off” in reverse order The resulting output should print the characters in reverse order.
Some things to note:
Some useful instructions:
lb, sll,sb, lb $t0,1($sp), , sb $t0,1($sp), addi $sp,$sp,1 and ), addi $sp,$sp,4
Screenshot
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Program
#Data declaration part
.data
input: .asciiz "Enter a 4 letter string: "
buff: .byte 5
#Program starts here
.text
#Display prompt
addi $v0,$0,4
la $a0,input
syscall
#read string
addi $v0,$0,8
la $a0,buff
addi $a1,$0,5
syscall
#Call method to reverse
jal reverse
#End of the program
addi $v0,$0,10
syscall
#Reverse function
reverse:
#Allocate stack
addi $sp,$sp,-16
#store each characters into registers
lbu $t0,($a0)
lbu $t1,1($a0)
lbu $t2,2($a0)
lbu $t3,3($a0)
#store each characters into stack
sb $t0,($sp)
sb $t1,4($sp)
sb $t2,8($sp)
sb $t3,12($sp)
#For next line
addi $v0,$0,11
li $a0,10
syscall
#Pop in reverse order
lbu $a0,12($sp)
addi $v0,$0,11
syscall
lbu $a0,8($sp)
addi $v0,$0,11
syscall
lbu $a0,4($sp)
addi $v0,$0,11
syscall
lbu $a0,0($sp)
addi $v0,$0,11
syscall
#de allocate stack
addi $sp,$sp,16
#return
jr $ra
-----------------------------------------
Output
Enter a 4 letter string: HELL
LLEH
-- program is finished running --
MIPS QUESTION This project will entail reading in a string of 4 characters into a variable...
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Spim question. Program and answer already given please explaine it.
Please explain the reason why each instruction was used
throughout the program step by step given the prompt, what is its
purpose to achive the goal asked in the prompt, why is written in
that order.
Please not just write to the side what each instruction means
in words like load $t0 to $t1. I want to understand the program
thoroughly.
Thanks in advance
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