a tennis ball is released from rest. (g= 9.8 m/s^2) Calculate the distance it falls in...
Homework Answers
According to motion equation
V=u+at
= 0+9.81×t=3*9.8=29.4m/s
So 29.4 will be object velocity after 3sec.
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tennis ball is released from rest. (g= 9.8 m/s^2)
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mass is 57.0 g and the collision's coefficient of restitution is
0.630.(Figure 2) In the figure, ?1=30.0?
and?1=20.0?. What is (vA)1, the
velocity of tennis ball A, immediately before the
collision?
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