If X represents a random variable coming from a normal distribution with mean 5 and if P(X>6.2)=0.28, then P(5<X<6.2) = 0.22
Can you please explain this step by step with an explanation, please?
here since mean is at 5, and for normal distribution is symmetric therefore equal proportion of area on both sides of 5
therefore P(X<5)= 0.5
P(X<6.2) =1-P(X>6.2)=1-0.28 =0.72
P(5<X<6.2) =P(X<6.2)-P(X<5) =0.72-0.50 =0.22
If X represents a random variable coming from a normal distribution with mean 5 and if...
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Assume Z is a random variable with a standard normal distribution and c is a positive number. If P(Z > c) = 0.25, then PC – c< < c) = 0.5. O True OFalse Exactly 50% of the area under the normal curve lies to the left of the mean. O True OFalse If X represents a random variable coming from a normal distribution and P(X < 5.2) = 0.5, then P(X > 5.2) = 0.5. O True O False
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