In a mouse dihybrid incross, how many embryos must you collect to have a 95% chance...
In a mouse dihybrid incross, how many embryos must you collect to have a 95% chance of getting at least one double mutant? Remember that 95% is 19/20.
Homework Answers
according to law of independent assortment for heterozygous dihybrid population the traits segregates in a genotypic ratio of 1:2:1:2:4:2:1:2:1. meaning that the probability of getting any specific homozygous trait is 1 out of 16 i.e 6.25% therefore in order to get probability of 95% you will need to collect at least 244 embryos so that you will get confirm double mutant.
(calculation be like 6.25% = 16 embryos, therefore for 95%= (16*95)/6.25 = 243.2)
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In a mouse dihybrid incross, how many embryos must you collect
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