In a survey of 1,532 former UF students, 84% said they were still in love with Tim Tebow. The survey's sampling error was 2%. Using this information, construct a confidence interval for the proportion of all former UF students who are still in love with Tim Tebow.
p^ = 0.84
E = 0.02
Interval Lower Limit = p̂ - E = 0.84000
- 0.02000 = 0.82
Interval Upper Limit = p̂ + E = 0.84000
+ 0.02000 = 0.86
confidence interval is ( 0.820 <
p < 0.860 ) or (82% < p < 86%
)
In a survey of 1,532 former UF students, 84% said they were still in love with...
In a study conducted in March 2020, 144 of 200 randomly selected students said that Liverpool football team were their favourite team. (a) Construct a 98% confidence interval to estimate the true proportion of students who said that Liverpool football team were their favourite team. (b) How large a sample would be necessary to estimate the true proportion of with a margin of error of 5%, with 95% confidence?
Suppose a survey revealed that 24% of 481 respondents said they had in the past sold unwanted gifts over the Internet. (a) Use the information to construct a 90% confidence interval for the population proportion who sold unwanted gifts over the Internet, rounding your margin of error to the nearest hundredth. (Round your answers to two decimal places.) ( (b) Use the information to construct a 98% confidence interval for the population proportion who sold unwanted gifts over the Internet,...
In a survey of 385 students at Broward College, North Campus, results revealed that 154 students were born outside of the USA. Construct a 96% confidence interval estimate for the proportion of students who were born outside the USA. Show your calculations on a separate sheet of paper for p-hat. Q-hat, the margin of error and the construction of the confidence interval. Also, give your interpretation of the confidence interval estimate. SHOW WORK
1. In an August 2012 Gallup survey of 1,012 randomly selected U.S. adults (age 18 and over), 53% said that they were dissatisfied with the quality of education students receive in kindergarten through grade 12. The bootstrap distribution (based on 5,000 samples) is provided. a). Would it be appropriate to use the normal distribution to construct the confidence interval in this situation? Explain briefly. b). The standard error from the bootstrap distribution is SE = 0.016. Use the normal distribution...
5) In a recent presidential election, 500 voters were surveyed and 350 of them said that they voted for the candidate who won. a. Construct a 96% confidence interval estimate of the percentage of voters who said they voted for the candidate who won. b. How many voters must they survey if they want 90% confidence that the sample proportion is in error by no more than 0.02?
In a survey of 3,641 travelers 1,536 said that location was very important for choosing a hotel and 1,185 said that reputation was very important in choosing an airline. (a) Construct a 95% confidence interval estimate for the population proportion of travelers who said that location was very important for choosing a hotel. 0.4059 ≤ π ≤ 0.4379 (Ans.) (b) Construct a 95% confidence interval estimate for the population proportion of travelers who said that reputation was very important in...
8.4.21 A past survey of 1.068.000 students taking a standardized test revealed that 84% of the students were planning on studying engineering in callege in a recent suney of 146 00n te SA 52% be planning to study engineering Construct a 95% confidence interval for the diference betveen propertions py-P by using the floeing inegualty Aume the sanples andn nd dpndet untie H0 A A P191 P292 (4-) <P1-P2 P191 P22 +2 fit The confidence interval is (Round to three...
In a recent survey of 114 WMU graduates, 52 students said that parking was too limited on campus. What is the estimate of the population proportion? What is the standard error of this estimate? Question 1 options: 1) Estimate of proportion: 0.456, Standard error: 0.0044. 2) Estimate of proportion: 0.456, Standard error: 0.0466. 3) Estimate of proportion: 0.544, Standard error: 0.0466. 4) The true population proportion is needed to calculate this. 5) Estimate of proportion: 0.544, Standard error: 0.0044. Question...
first picture is the information
2-) In a survey of 1000 U.S. teen. 372 said that they own smartphones. Find a point estimate for the population proportion of U.S. teens who own smartphones 2-) Use the data given in Example 2 to construct a 90% confidence interval for the population proportion of U.S. teens who own a smartphone
In a survey of 4074 adults, 728 oppose allowing transgender students to use the bathrooms of the opposite biological sex. Construct a 99% confidence interval for the population proportion. Interpret the results. A 99% confidence interval for the population proportion is (LL) (Round to three decimal places as needed.) nterpret your results. Choose the correct answer below. O A. With 99% confidence, it can be said that the population proportion of adults who oppose allowing transgender students to use the...