When a particle rotates in a circle, a force acts on it directed toward the center of rotation. Does this force perform a work on the particle?
True or False
Here,
for the total work done
as work done = force * displacement * cos(theta)
as theta = 90 degree
the work done = force * displacement * 0
work done = zero
the work performed is zero
the correct answer is
False
When a particle rotates in a circle, a force acts on it directed toward the center...
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A particle moves through an xyz coordinate system while a force
acts on the particle. When the particle has the position vector
r
= (2.00 m) - (3.00 m) + (2.00 m) , the force is F
= Fx + (7.00 N) - (6.00 N) , and the corresponding torque about the
origin is T
= (4.00 N·m) + (10.0 N·m) + (11.0 N·m) . Determine Fx.
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