Question

How do I get this answer use integrated rate law for 1st order reaction ln[SO2Cl2] =...

How do I get this answer

use integrated rate law for 1st order reaction
ln[SO2Cl2] = ln[SO2Cl2]o - k*t
ln[SO2Cl2] = ln(0.125) - 1.38*10^-4*460
ln[SO2Cl2] = -2.0794 - 1.38*10^-4*460
ln[SO2Cl2] = -2.1429
[SO2Cl2] = 0.117 M
Answer: 0.117 M

lm lost going from -2.1429 to 0.117

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
How do I get this answer use integrated rate law for 1st order reaction ln[SO2Cl2] =...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Which of the following represents the integrated rate law for a first-order reaction? Group of answer...

    Which of the following represents the integrated rate law for a first-order reaction? Group of answer choices [A]t - [A]o = - kt = - kt k = Ae(-Ea/RT) = + lnA - = kt

  • 44) Which of the following represents the integrated rate law for a first-order reaction? A) I...

    44) Which of the following represents the integrated rate law for a first-order reaction? A) I (Alt kt Α) ΙΑ]ο. B) 1 . 1 .kt [A] [A] C) [A]:-[A]o - kt D) k = Ae(Ea/RT) E) Inkla (1) 5) mk2 RW 45) Which of the following represents the integrated rate law for a second-order reaction? A) ITALO B) [A] [A]. = kt C) [A]o - [A] = - kt D) k = Ae(Ea/RT) E E) In ki - Ea (1)...

  • 44) Which of the following represents the integrated rate law for a first-order reaction? A) In...

    44) Which of the following represents the integrated rate law for a first-order reaction? A) In Alt E-kt TA) B) 1 . 1 .kt Alt Alo C) [Alt-[Al= kt D) k = Ae(Ea/RT) E) IN (1+ Ina 45) Which of the following represents the integrated rate law for a second-order reaction? A) ISAI. -- - B) TÁL TAL. - Lt C) [A]o - [A] =-kt D) k = Ac(Ea/RT) E 1). Ina 46) Which of the following represents the integrated...

  • The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they...

    The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line, y=mx+by=mx+b. Order Integrated Rate Law Graph Slope 0 [A]=−kt+[A]0[A]=−kt+[A]0 [A] vs. t[A] vs. t −k−k 1 ln[A]=−kt+ln[A]0ln⁡[A]=−kt+ln⁡[A]0 ln[A] vs. tln[A] vs. t −k−k 2 1[A]= kt+1[A]01[A]= kt+1[A]0 1[A] vs. t1[A] vs. t kk A.) The reactant concentration in a zero-order reaction was 0.100 MM after 165 ss and 4.00×10−2 MM after 305 ss . What is the...

  • The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they...

    The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line, y=mx+by=mx+b. Order Integrated Rate Law Graph Slope 0 [A]=−kt+[A]0[A]=−kt+[A]0 [A] vs. t[A] vs. t −k 1 ln[A]=−kt+ln[A]0ln⁡[A]=−kt+ln⁡[A]0 ln[A] vs. tln[A] vs. t −k 2 1[A]= kt+1[A]01[A]= kt+1[A]0 1[A] vs. t1[A] vs. t k Part A The reactant concentration in a zero-order reaction was 8.00×10−2 MM after 130 ss and 4.00×10−2 MM after 380 ss . What is...

  • + Using Integrated Rate Laws The integrated rate laws for zero-, first-, and second-order reaction may...

    + Using Integrated Rate Laws The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line, y = mx + b. Slope Order O 1 2 Integrated Rate Law Graph [A] = - kt + [A] [A] vs. t In[A] = -kt + In[A], In[A] vs. t LÀ=kt + TA LÀ vs. t -k Review Constants Periodic Table Part A The reactant concentration in a zero-order reaction was...

  • + Using Integrated Rate Laws The integrated rate laws for zero-, first-, and second-order reaction may be arrang...

    + Using Integrated Rate Laws The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line, y = mx + b. Slope Order O 1 2 Integrated Rate Law Graph [A] = - kt + [A] [A] vs. t In[A] = -kt + In[A], In[A] vs. t LÀ=kt + TA LÀ vs. t -k Review Constants Periodic Table Part A The reactant concentration in a zero-order reaction was...

  • 2- The integrated form of the pseudo rate law depends on thereaction order with respect to...

    2- The integrated form of the pseudo rate law depends on thereaction order with respect to CV. The integrated rate laws for y=1 (1st order) and 2 (2nd order) are given in Equations 3 and 4. Compare each with the general form of a linear equation, y=mx+b. In[CV]t = - k't + In[CV]0 (3) 1/[CV]t = k't + 1/[CV]O (4)

  • B) Determine the integrated rate law for this reaction. C) Calculate the half-life for this reaction....

    B) Determine the integrated rate law for this reaction. C) Calculate the half-life for this reaction. D) How much time is required for the concentration of A to decrease to 4.25x10^-3 M A certain reaction has the following general form: At a particular temperature and Alo 3.40 × 10-2 M concentration versus time data were collected for this reaction, and a plot of ln A versus time resulted in a straight line with a slope value of -2.91 x 10-2...

  • ± Using Integrated Rate Laws Part A The reactant concentration in a zero-order reaction The integrated...

    ± Using Integrated Rate Laws Part A The reactant concentration in a zero-order reaction The integrated rate laws for zero-, first-, and second order reaction may be arranged such that they resemble the equation for a straight line y=mx + b was 9.00x102 M after 155 s and 3.50x102 M after 320 s. What is the rate constant for this reaction? Express your answer with the appropriate units Indicate the multiplication of units, as necessary explicitly either with a multiplication...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT