3. An insulating cylindrical shell of radius 5mm has a linear charge density of 25μC/m spread...
3. An insulating cylindrical shell of radius 5mm has a linear charge density of 25μC/m spread evenly over its outer surface. What is the potential difference between the surface of the cylinder and a point 2cm above the surface? (Answer: 1.51X105V)
Homework Answers
Data given.
Linear charge density, lambda = 25 uC/m
Here outer distance,
r2=5 +2 =7 cm
Inner distance r1= 5cm
Write the expression to calculate the potential difference between the surface of the cylinder and a point 2cm above the surface.
V= (lambda/2pieo)ln(r2/r1)
V= ( 25 *10^-6/2pi*8.85*10^-12)ln(7/5)
V= 1.51 ×10^5 V
Please rate positive if it is correct
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