which of the following atoms is diamagnetic in its ground state? Cu As none of these Ca Fe
cu = atomic number =29 electronic configuration [ 1S2 2S2
2P6 3S2 3P6 4S1 3d10] although it consists of lone electron but it
is diamagnetic
As = atomic number =33 electronic configuration [ 1S2 2S2 2P6 3S2 3P6 4S2 3d10 4p3] three unpaired electrons so para magnetic
Ca = atomic number = 20 electronic configuration [ 1S2 2S2 2P6 3S2 3P6 4S2 ] it is diamagnetic because of metallic nature
Fe = atomic number = 26 electronic configuration [ 1S2 2S2 2P6 3S2 3P6 4S2 3d6 ] it is a ferro magnetic (spins are aligned anti parallel )
answer => cu
To determine which atom is diamagnetic in its ground state, we need to understand that diamagnetic atoms have all their electrons paired up (no unpaired electrons).
Let's check each option:
Cu (Copper):
Atomic number: 29
Electron configuration: [Ar] 4s¹ 3d¹⁰
The 4s electron is unpaired, so paramagnetic.
As (Arsenic):
Atomic number: 33
Electron configuration: [Ar] 4s² 3d¹⁰ 4p³
The 4p subshell has 3 unpaired electrons, so paramagnetic.
Ca (Calcium):
Atomic number: 20
Electron configuration: [Ar] 4s²
All electrons are paired, so diamagnetic.
Fe (Iron):
Atomic number: 26
Electron configuration: [Ar] 4s² 3d⁶
The 3d subshell has unpaired electrons, so paramagnetic.
Calcium (Ca) is the only diamagnetic atom in this list because all its electrons are paired.
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