Question

IN C++

Write a function numberOfOddNumbers that takes an array of integers and its size (length) as parameters and then returns the number of the odd numbers found in the array. For example, if an array called list stores the following values:

int list []= { 1,1, 8,6,9,4,3,9595,0 };

Then the call of numberOfOddNumbers (list,9) should return 5.

If instead, the list had stored these values:

int list2[] = { 2, 4, 6, 8, 10, 208 };

Then the call (  numberOfOddNumbers (list2,6) ) should return 0 because all the numbers in the array list2 are even.

Answer 1

#include<iostream>
#include<iomanip>
using namespace std;

int numberOfOddNumbers(int arr[], int size){
    int count = 0;
    for(int i = 0;i<size;i++){
        if(arr[i]%2==1){
            count++;
        }
    }
    return count;
}

int main(){
    int list []= { 1,1, 8,6,9,4,3,9595,0 };
    cout<<numberOfOddNumbers(list, 9)<<endl;
    
    int list2[] = { 2, 4, 6, 8, 10, 208 };
    cout<<numberOfOddNumbers(list2, 6)<<endl;
    
    return 0;
}

int numberOfOddNumbers(int arr[], int size){
    int count = 0;
    for(int i = 0;i<size;i++){
        if(arr[i]%2==1){
            count++;
        }
    }
    return count;
}