A rolling operation produces parts that are normally distributed with a mean thickness of 0.220 in and a sd of 0.002 in. If specs call for 0.225 plus 000 minus 0.008, what percentage of the parts will be in spec?
85.1%
87.7%
92.7%
98.3%
Sol:
sample follows normal distribution
mean=0.220
sd=0.002
P(0.225-0.008<X<0.225+0.008)
P(0.217<X<0.233)
using R code:
library(tigerstats)
pnormGC(bound=c(0.217,0.233),region="between",
mean=0.220,sd=0.002,graph=TRUE)

ANSWER:
92.7%
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