Systronics is considering introducing a new solvent that is biodegradable and that they believe has a 60% chance of being successful. If this product is successful, Systronics expects the net profit will be $50 million. If unsuccessful the net loss is expected to be $20 million.
(a)
| States of nature | Expected | ||
| Alternatives | Successful | Unsuccessful | payoff |
| Introduce | 50 | -20 | 22 |
| Don't introduce | 0 | 0 | 0 |
| Probability | 0.6 | 0.4 | |
| Opportunity loss | States of nature | Expected | |
| Alternatives | Successful | Unsuccessful | OL |
| Introduce | 0 | 20 | 8 |
| Don't introduce | 50 | 0 | 30 |
| Probability | 0.6 | 0.4 | |
As per the Baye's decision rule, we will take the alternative which minimizes the expected opportunity loss i.e. to Introduce.
(b)
Expected value of perfect information = Expected opportunity loss = $8 million
(c)
Define events as:
IS = Test approved
IF = Test failed
S = Actual success in the broad market
F = Actual failure in the broad market
Given is Priors i.e. P(S) = 0.6 and P(F) = 0.4 and conditionals i.e. P(IS | S) = 0.80 and P(IS | F) = 0.15.
Use the Baye's rule using the following table to compute the posteriors.
| IS | |||||||
| Prior | Conditional | Joint | Posterior | ||||
| P(S) | 0.6 | P(IS|S) | 0.8 | P(S) x P(IS|S) | 0.48 | P(S|IS) | 0.89 |
| P(F) | 0.4 | P(IS|F) | 0.15 | P(F) x P(IS|F) | 0.06 | P(F|IS) | 0.11 |
| Total | 1 | P(IS) | 0.54 | 1 | |||
| IF | |||||||
| Prior | Conditional | Joint | Posterior | ||||
| P(S) | 0.6 | P(IF|S) | 0.2 | P(S) x P(IF|S) | 0.12 | P(S|IF) | 0.26 |
| P(F) | 0.4 | P(IF|F) | 0.85 | P(F) x P(IF|F) | 0.34 | P(F|IF) | 0.74 |
| Total | 1 | P(IF) | 0.46 | 1 | |||
(i)
Decision tree

(ii)
The optimal decision is to go for the test and then introduce if the test shows success; don't introduce otherwise.
(iii)
Expected monetary value = 22.80 million
(iv)
Willing ot pay = 22.80 - 22 = 0.80 million or less
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