Question

For every set A and B,

for example A=[A,B]. B=[B,D,E]

Use java or python to crate 4 function:

1: union

A union B = [A,B,D,E]

2: intersection

A intersection B = [B]

3: A-B =[A]

4: subset (boolean)

False

Answer 1

Here is the completed code for this problem in Python. Comments are included, go through it, learn how things work and let me know if you have any doubts or if you need anything to change. If you are satisfied with the solution, please rate the answer. Thanks

Note: Please maintain proper code spacing (indentation), just copy the code part and paste it in your compiler/IDE directly, no modifications required.

#code

'''
Implementation of required functions in Python using lists.
You can also use sets instead of lists, so that we dont need to check 
for duplicate values.
'''

#method to implement union of setA and setB
def union(setA, setB):
    #creating a list to store the result
    result=[]
    #adding each element of setA to result
    for i in setA:
        result.append(i)
    #adding each element of setB to result, avoiding duplicates
    for i in setB:
        if i not in result:
            result.append(i)
    #returning result
    return result

#method to find the intersection of setA and setB
def intersection(setA, setB):
    result=[]
    #looping through each element in setA, adding to setB only if
    #the element is present on setB also
    for i in setA:
        if i in setB:
            result.append(i)
    return result

#method to find the set difference of setA and setB
def difference(setA, setB):
    result=[]
    # looping through each element in setA, adding to setB only if
    # the element is NOT present on setB
    for i in setA:
        if i not in setB:
            result.append(i)
    return result

#method to check if setA is a subset of setB
def subset(setA, setB):
    #looping and checking if all elements of setA is present on setB
    for i in setA:
        if i not in setB:
            #current element of setA is not present in setB
            return False
    return True #subset



#creating two sets and demonstrating all operations
A=['A','B','C','D']
B=['C','D','E','F']
print('A =',A)
print('B =',B)
print('A union B =',union(A,B))
print('A intersection B =',intersection(A,B))
print('A - B =',difference(A,B))
print('B - A =',difference(B,A))
print('A subset of  B =',subset(A,B))

#output