Question

How you find left hand riemann sum of a function with interval (0,1) in python?

Answer 1

Program:

import numpy as np

f = lambda x : 1/(1+x**2)            #function
a = 0; b = 1; N = 10

dx = (b-a)/N                       #interval
x_left = np.linspace(a,b-dx,N)

left_riemann_sum = np.sum(f(x_left) * dx)       #finding sum f(x)*dx
print("\nLeft Riemann Sum:",left_riemann_sum)
print("")

Screenshot: ( for reference )

Output:

Note: If you have any doubts please comment.

It will be great help If you like.