A wooden block with mass 1.50 kg is placed against a compressed spring at the bottom...
A wooden block with mass 1.50 kg is placed against a compressed spring at the bottom of a slope inclined at an angle of 29.0 ∘ (point A). When the spring is released, it projects the block up the incline. At point B, a distance of 7.15 m up the incline from A, the block is moving up the incline at a speed of 7.50 m/s and is no longer in contact with the spring. The coefficient of kinetic friction between the block and incline is μk = 0.40. The mass of the spring is negligible.
Calculate the amount of potential energy that was initially stored in the spring.
Take free fall acceleration to be 9.80 m/s2m/s2 .
The answer is 130 J, But I want to know why the force of gravity that is parallel to the force of friction isn't included when calculating the work over the distance. I had originally thought that the W = (5.14N + 14.7sin(29)N)(7.15m)
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A wooden block with mass 1.50 kg is placed against a compressed
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