4) You are given a copper bar of dimensions 3 cm × 5 cm × 8...
Homework Answers
Since resistance is given by,
R = rho*l/A
So, R is proportional to (length/area) ratio
therefore for smallest resistance (l/A) ratio should be minimum,
when length is 3 cm, then l/A = 3/(5*8) = 0.075 1/cm
when length is 5 cm, then l/A = 5/(3*8) = 0.208 1/cm
when length is 8 cm, then l/A = 8/(3*5) = 0.533 1/cm
l/A is minimum when we take length 3 cm ,then area = (5*8) cm^2
So, we have to take the according to the 3cm length.
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