Question

Methanol can be formed by the following unbalanced equation below. How many grams of methanol can be formed from 101 molecules of CO? H2(g) + CO(g) = CH3OH(l)

Answer 1

The Balanced equation is

CO. + 2 H2 ------> CH3OH

1 mole. 1 mole

We know that 1 mole CO = 6.023 x 10²³ CO molecules

1 mole CH3OH = Molecular weight of CH3OH

= 12 + (4 x1) + 16

= 32 g / mole

6.023 x 10²³ CO molecules = 32 g / mole CH3OH

101. CO molecules. = Y

Y = 101 x 32 g mole-1 / 6.023 x 10²³

Y = 536.61 x 10^-23 g mole-1 CH3OH