A 5.10 kg block hangs from a spring with spring constant 1760 N/m . The block is pulled down 6.80 cm from the equilibrium position and given an initial velocity of 1.20 m/s back toward equilibrium.
A) What is the frequency of the motion?
B) What is the amplitude?
C)What is the total mechanical energy of the motion?
A 5.10 kg block hangs from a spring with spring constant 1760 N/m . The block...
A 5.40 kg block hangs from a spring with spring constant 2020 N/m . The block is pulled down 6.10 cm from the equilibrium position and given an initial velocity of 1.20 m/s back toward equilibrium. a. What is the frequency of the motion? b. What is the amplitude? c. What is the total mechanical energy of the motion?
Review PartA A 4.70 kg block hangs from a spring with spring constant 2180 N/m. The block is pulled down 4.30 cm from the equilibrium position and given an initial velocity of 1.00 m/s back toward equilibrium. What is the frequency of the motion? Express your answer with the appropriate units. Value Units Submit Reguest Answer - Part B What is the amplitude? Express your answer with the appropriate units. Value Units Submit ▼ Part C What is the total...
A 1.10 kg mass hangs from a spring of force constant 400 N/m . The mass is then pulled down 13.0 cm from the equilibrium position and released. At the end of five complete cycles of vibration, the mass reaches only 10.0 cm from the equilibrium position. Part A: How much mechanical energy is lost during these five cycles? Part B: What percentage of the mechanical energy is lost during the five cycles?
A 5 kg block hangs from a spring with spring constant 5 N/m. At t=0s the block is 3 m below the equilibrium point and moving upward with a speed of 6 m/s. What is the amplitude of the oscillations?
The force of constant of a spring of spring pendulum is 50N/m. A block of mass 0.5 kg, attached to it is pulled through a distance of 0.01 m before being released. Calculate the following expressions: a) the time period and frequency b) velocity amplitude and acceleration amplitude; c) the time required by the block to move half-way towards the center from its initial position d) total energy of the system.
A classic spring/block system is moving back and forth on an air track (no friction). The mass of the block is 0.5 kg and the spring constant is 200 N/m. The mass is pulled back from equilibrium and then quickly pushed into motion such that it has an initial speed at the release point (60 cm from the equilibrium position) of 5.0 m/s. Determine the frequency of this oscillator.
A 180 g block hangs from a spring with spring constant 15 N/m . At t=0s the block is 21 cm below the equilibrium point and moving upward with a speed of 89.0 cm/s . What is the block's oscillation frequency? What is the block's distance from equilibrium when the speed is 30 cm/s ? What is the block's distance from equilibrium at t=1.0s?
A 160 gg block hangs from a spring with spring constant 7.0 N/m . At t=0s the block is 20 cm below the equilibrium point and moving upward with a speed of 125 cm/s . What is the block's oscillation frequency? What is the block's distance from equilibrium when the speed is 39 cm/s ? What is the block's distance from equilibrium at t=6.0s Show work please.
A 2-kg object is suspended at rest from a vertical spring (K=196 N/m) attached to the ceiling. From this equilibrium position, the object is pulled down an additional distance d=3 cm and released from rest. a) Considering the upward direction to be positive, find the amplitude, frequency and phase constant of the simple harmonic motion and write the equation of the motion. b) find the speed of the object at the moment when it is 3 cm above the release...
A block of mass m = 4.5 kg is attached to a spring with spring constant k = 710 N/m. It is initially at rest on an inclined plane that is at an angle of θ = 25° with respect to the horizontal, and the coefficient of kinetic friction between the block and the plane is μk=0.18. In the initial position, where the spring is compressed by a distance of d = 0.12 m, the mass is at its lowest...