f = mu0 I1 I2 / 2 pi r
0.25 = (4 pi * 10-7 * I2) / (2 pi * 0.03)
I = sqrt [(0.25 * 2 pi * 0.03) / (4 pi * 10-7)]
I = 193.6 A
The force per meter between the two wires of a jumper cable being used to start...
The force per meter between the two wires of a jumper cable being used to start a stalled car is 0.23 N/m. What is the current in the wires, given they are separated by 2.00 cm?
Home I Student: lewis jes HW-6 Spring19 Begin Date: 3/20 2019 12:01 (1296) Problem 5: The force per meter between the two wires of a Jumper . Due Date: I End Date: cable being used to start a stalled car is 0.245 N/m. 丶 & what is the current in the wires, given they are separated by 2.00 cm? Grade Summa al Deductions Potential sin( ) | cos() | tan() π l ( 171819 cotan asn0 atano acotan) sinh Submissions...
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Jumper cables used to start a stalled vehicle often carry a 65-A current. How strong is the magnetic field 2.5 cm from one cable? Express your answer to two significant figures and include the appropriate units.
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The force per unit length on two long parallel wires is measured to be 6.3 × 10−5 N/m when they are separated by 2.4 cm. What is the new force distribution (in N/m) when the two wires are moved to a distance of 1.2 cm and the current in each of the wires is tripled?