A skydiver is at a standard altitude of 12,000 ft and is falling at a rate...

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A skydiver is at a standard altitude of 12,000 ft and is falling at a rate...

A skydiver is at a standard altitude of 12,000 ft and is falling at a rate of 180 ft/s. What rate of change of ambient pressure (in units of lb/ft^2/s) does this person experience?

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Answer 1

Answer #1

12000 ft = 3657.6 m

acceleration due to gravity, g = 9.8 m/s^2

Ambient pressure, P = Po e^(-gMh/Ro To)

dP/dt = Po e^(-gMh/Ro To) (-gM/Ro To) (dh/dt)

dP/dt = 2116.22 x e^(-9.8 x 0.0289 x 3657.6/8.314 x 288) x (-9.8 x 0.0289 /288 x 8.314) x 180

dP/dt = 3.22 x 10^-4 lb/ft^2 sec

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Answer 2

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