For a 1GHz processor computer, compute clock cycle time.
Clock cycle time is defined as the reciprocal of clock frequency.
In your case, the clock frequency is 1GHz which is 109 Hz.
Hence, clock cycle time = 1/frequency = 1/109 = 10-9 = 1.0 ns(nano seconds).
In this exercise, we examine how pipelining affects the clock cycle time of the processor. Problems in this exercise assume that individual stages of the datapath have the following latencies: IF | ID | EX | MEMIwB 200ps 400ps 150ps 250ps 200ps Also, assume that instructions executed by the processor are broken down as follows: alu beqIwSW 45% 20% 20% 15% 3.1 What is the clock cycle time in a pipelined and non-pipelined processor? 3.2 What is the total latency...
In this exercise, we examine how pipelining affects the clock cycle time of the processor. Problems in this exercise assume that individual stages of the datapath have the following latencies: [17pts] 3. IF ID EEX MEM | WB 250ps 350ps 150ps300ps200ps a. what is the clock cycle time in a pipelined and non-pipelined (ie, single cycle) processor? what is the total latency of one lw instruction in a pipelined and non-pipelined (i.e., single cycle) processor? b. What is the total...
Given a processor that runs at 1GHz with the following: Instruction-------------- Frequency --------------Cycles Load & store ----------------25% --------------------10 arithmetic instructions------ 65% --------------------6 branch instructions -----------10%-------------------- 4 1) Calculate the CPI for the above. 2) Suppose the amount of registers are doubled, such that clock cycle time increases by 40%. What is the new clock speed (in GHz)? 3) Assume only the load & stores instructions are speed up by 5 times and their frequency is increased to 50% (Arithmetic instructions...
Processor 1 is on a 4-stage pipeline on a 12ns clock cycle. Processor 2 is on a 10-stage pipeline on a 4ns clock cycle. Which processor has the better latency? Which processor has better maximum throughput? Assuming 25% of all instructions on P1 require a 1-cycle stall, what is its throughput?
Figure 1: each block gives the number of different types of instructionsConsider a program with the execution flow shown in Figure 1. There are in total 3 types of instructions used in this program: Type 1 (in-processor calculation): execution rate as 1 per clock cycle; Type 2 (memory access): each instruction takes 2 clock cycles for execution; Type 3 (loop control): each instruction takes 2 clock cycles for jump into the loop block or 3 clock cycles for jump to the block after...
In a non-pipelined processor, the clock cycle is determined by the shortest possible path in a processor. Group of answer choices true false
10 decade counters are cascaded determine frequancy if clock is 1GHZ.
Q.4 [10 points] A processor is designed such that the clock of the processor runs at 2.0 GHz. The following table gives the instruction frequencies for the benchmark and how many cycles each instruction takes. Instruction Type Frequency Cycles Load & Stores 25% 8 cycles Arithmetic Instructions 60% 6 cycles Branch instructions 15% 4 cycles (a) (2 points) Calculate the CPI for the above benchmark. (b) (4 points) Suppose the amount of registers are doubled, such that clock cycle time...
A non-pipelined processor has a clock rate of 1 GHz and an average instruction takes 9 cycles to execute. The manufacturer has decided to design a pipelined version of this processor. For this purpose, the instruction cycle has been divided into five stages with the following latencies: Stage 1 – 2.0 ns,Stage 2 – 1.5 ns, Stage 3 – 1.0 ns, Stage 4 – 2.6 ns, Stage 5 – 1.9 ns. Each stage will require an extra 0.4 ns for...
A processor is designed such that the clock of the processor runs at 1 GHz. The following table gives the instruction frequencies for the benchmark and how many cycles each instruction takes. Instruction Type Frequency Cycles Load & Stores 25% 10 cycles Arithmetic Instructions 65% 6 cycles Branch instructions 10% 4 cycles (a) Calculate the CPI for the above benchmark. (b) Suppose the amount of registers are doubled, such that clock cycle time increases by 40%. What is the new...