No, we cannot determine the rate of reaction
with only the entropy change (
)
or a change in free energy (
)
known to us. A Chemist needs other parameters to qualitatively or
quantitatively make reasonable assumptions about how fast the
reaction will proceed. These parameters, on a basic level, are
introduced in the collision model for the rates of reactions,
According to this model, the rate of reaction (or reaction
kinetics) is dependent on three main parameters, viz., collision
frequency (z), activation energy (Ea), and the probability (or
orientation) factor (p). These factors, in turn, are dependent on
the reaction conditions, which include concentrations of reactants
or products, temperature, and pressure. For example, if the
reactants are in higher concentrations, there will be a greater
number of collisions between them, which will also increase the
number of collisions that occur with enough energy (greater than or
equal to Ea) or with the correct orientation. Eventually, the rate
of reaction will increase with increasing reactant
concentration.
On the other hand, thermodynamic quantities like change in free
energy (
)
are only concerned with whether a reaction will occur under given
conditions or not. It is not concerned with the rate or speed with
which the reactants will be converted to products.
is related to entropy change (
)
and enthalpy change (
)
through the Gibbs free energy equation whose simple representation
is written below:

In the above equation, if
, T, and
have such values that the value of
comes out to be negative or less than zero, then the process or a
chemical reaction can theoretically occur spontaneously in the
specified direction, i.e. from reactants to products. Contrarily,
if
is greater than zero, the chemical reaction will not occur in the
specified direction. In fact, then the reverse reaction can
theoretically occur spontaneously. These predictions will be based
on the initial and final states but will not give any information
about the time required for the process.
A Chemist needs information from both thermodynamics and
kinetics to fully explain the chemical reaction. Thermodynamics
cannot predict the rate of reaction but the reverse is not
true. That is, if a chemical reaction is taking place with a rate
having a positive magnitude, then it is obvious that its
is less than zero or it is spontaneous under those conditions.
can you determine the rate of reaction with only the entropy (delta G of reaction)?
Question 12 When delta G is negative (1 point)* entropy is high and enthalpy low entropy low and enthalpy high when entropy is negative when entropy is zero Question 13 Question 13 When delta G is negative (1 point) * O initial G is high and final G is low initial G is low and final G is high intial G is in equilibrium with final G O none Question 14 When delta G is negative (1 point) * O...
Calculate the Entropy of the reaction equilibrium between 2NO2 - N2O4 given the equation: Delta G = Delta H - T Delta S where: Enthalpy = -47.5 Kj/mol Gibbs free energy = -3.59 Kj/mol Temperature = 298K
Question 5 The spontaneity of a reaction depends both on the enthalpy change, Delta H, and entropy change, Delta S. Reactions that release energy produce more stable products, and the universe tends toward disorder. Thus, an exothermic reaction with a positive entropy change will always be spontaneous. Mathematically, this relationship can be represented as where Delta G is the change in Gibbs free energy and T is the Kelvin temperature. If Delta G is negative, then the reaction is spontaneous....
For the reaction NH4NO3(aq) ---->. N2O(g) + 2 H2O(l) Delta G° = -183.7 kJ and Delta H° = -149.6 kJ at 341 K and 1 atm. This reaction is (reactant, product)_______favored under standard conditions at 341 K. The entropy change for the reaction of 1.70 moles of NH4NO3(aq) at this temperature would be________ J/K.
Consider the reaction 2CO(g) + 2NO(g) rightarrow 2CO_2(g) + N_2(g) for which Delta H degree = -746.6 kJ and Delta S degree = -198.0 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 1.514 moles of CO(g) react under standard conditions at 298.15 K. (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If...
Predict the sign of the entropy change, Delta S degree, for each of the reaction displayed. Drag the appropriate items to their respective bins. Calculate the standard entropy change for the reaction 2Na(s) + CI_2 (g) rightarrow 2NaCl(s) using the data from the following table: Express your answer to four significant figures and include the appropriate units.
Calculate
rxn for the below combustion reaction, determine if
entropy increases or decreases. Assume 1 mol of substance at 25
Celsius.
C3H8(g) + 5O2(g)
3CO2(g) + 4H2O(l)
Delta G of C3H8 = -23.4 kj/mol
Delta G of O2 = 0 kj/mol
Delta G of CO2 = -394.36 kj/mol
Delta G of H2O = -237.1 kj/mol
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For the reaction H2(g) + S(s) --> H2S(g) delta H = -20.2 kJ mol-1 and delta S =+43.1 J K-1mol-1. Which of the following statements is true? The reaction is spontaneous at all temperatures. delta G becomes less favorable as T is raised. The reaction is only spontaneous at high temps. The reaction is only spontaneous at low temps. The reaction is at equilibrium at 25 C under standardconditions. Please explain why too. Thank you, feedback will beawarded as soon...
help
Determine the entropy change in the surroundings for the following reaction at 25.0 degree C: 4 NH_3(g) + 5 O_2(g) rightarrow 4 NO(g) + 6H_2O(g) Delta H_rxn = -906 kJ +6.95 kJ/K +3.04 kJ/K -1.14 kJ/K -2.82 kJ/K
Question 15 When delta G is negative (1 point) * None of the above O reaction is balanced in mass and energy O reaction is endothermic if entropy is positive reaction is exothermic if entropy is positive Question 16 When delta G is negative (1 point) * O None reactions are spontaneous because they were empirically determined and consistent with the theory Orx is at equilibrium Orx is non-spontaneous