A computer has 1,024 registers (numbered 0 to 1,023). Arithmetic instructions for this computer hold three...
A computer has 1,024 registers (numbered 0 to 1,023). Arithmetic instructions for this computer hold three register numbers. How many bits are needed to hold the register numbers?
Homework Answers
Answer : In the given problem , number of registers = 1024
number of bits required for a register = log 2(number of registers)
= log 2 (1024) = log 2(210) = 10
So , each register requires 10 bits
Since , computer holds three register numbers.
Number of bits needed to hold the register numbers = 3 * 10 = 30 bits.
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