Question

Python: Given a list named listOfThings, write a function that prints out if there are an odd number of things in the list or an even number of things in the list.

If there is an even number of things, your function should print

There is an even number of items in the list.

If there is an odd number of things, your function should print

There is an odd number of items in the list.

Use the following function header

def printOddOrEven(listOfThings)

Answer 1

def printOddOrEven(listOfThings):
e=0
o=0
for i in listOfThings:
if i%2==0:
e=e+1
o=o+1
if e>0:
print("There is an even number of items in the list.")
if o>0:
print("There is an odd number of items in the list.")
  

listOfThings = []
n = int(input("Enter number of elements : "))

for i in range(0, n):
ele = int(input())
listOfThings.append(ele)
printOddOrEven(listOfThings)