Question

In the following i need to print the number of parameters that are passed to main (args) as well as the actual parameters (*argv). These parameters are all printed to an output file named stdout.log. I run my program 3 times with a shell script and pass different number of parameters each time, however, after opening stdout.log the only thing in stdout.log is the content from the last call and the 3 prior runs are not there at all.

What needs to be done to my code so that after my script runs 3 times with different parameters i see all runs printed to my stdout.log instead of must my last run????

#include "SecondFile.hpp"

#include <iostream>

#include <fstream>

#include <string>

using namespace std;

int main( int args, char *argv[])

{

std:: cout << " Running 'hw1' with " << args << " arguments." << endl;

std:: cout << " stdout append to stdout.log " << endl;

std:: cout << " stderr append to stderr.log " << endl;

   ofstream outputFile("stdout.log");

   outputFile << " args was: " << args <<endl;

for( int i=0; i<args; i++){

   outputFile << argv[i] << endl;

   outputFile << endl;

}

   outputFile << " Done! " << endl;

SecondFile obj;

obj.printMethod(args, *argv);

   cout << endl;

   cout << endl;

return 0;

}

Answer 1

#include "SecondFile.hpp"
#include <iostream>
#include <fstream>
#include <string>

using namespace std;

int main(int args, char *argv[]) {
    std::cout << " Running 'hw1' with " << args << " arguments." << endl;
    std::cout << " stdout append to stdout.log " << endl;
    std::cout << " stderr append to stderr.log " << endl;
    ofstream outputFile("stdout.log", ios_base::app);
    outputFile << " args was: " << args << endl;
    for (int i = 0; i < args; i++) {
        outputFile << argv[i] << endl;
        outputFile << endl;
    }
    outputFile << " Done! " << endl;
    outputFile.close();
    SecondFile obj;
    obj.printMethod(args, *argv);
    cout << endl;
    cout << endl;
    return 0;
}