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How many grams of KOH would need to be added to 0.5 L of 0.25M NH4Cl...

How many grams of KOH would need to be added to 0.5 L of 0.25M NH4Cl soln to create pH=9.0. (Kb(NH3)=1.8x10^-5)

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Answer #1

first find mols of conjugate base NH3 from pH of buffer equation,and then write ICE table from it we can find mols of koh , multiply mols of koh with molar mass of koh to get mass of koh required to make pH=9.

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