Question

**IN PYTHON**

Given a range from 10-50, write a code in python that shows how many odd and even numbers there are, and list them out.

Answer 1

#Python program that finds the number of even number count
#and number of odd number count and print the results to python console
#main.py
def main():
    print('Finding number of even and number of odd values')
    #set counters to 0
    evenCount=0
    oddCount=0
    #create two empty lists
    evenList=[]
    oddList=[]

    #loop over range of 10 to 50
    for number in range(10,50):
        #check if number is even
        if number %2==0:
            evenList.append(number) #insert number to even list
            #increment evenCount by 1
            evenCount=evenCount+1
        else:
            oddList.append(number) #insert number to odd list
            # increment oddCount by 1
            oddCount=oddCount+1
    print('Finding count of even and odd count in a range of 10 to 50')
    print('Even number list : ',evenList)
    print('Odd number list : ', oddList)
    print('Number of even number count: ',evenCount)
    print('Number of odd number count: ', oddCount)
#calling main method
if __name__ == '__main__':
    main()

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Sample Output:

Finding number of even and number of odd values
Finding count of even and odd count in a range of 10 to 50
Even number list : [10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48]
Odd number list : [11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, 49]
Number of even number count: 20
Number of odd number count: 20