Question

Consider a ray of white light incident from air on a dispersive material at an angle of incidence of (42.5+A)^o. The red light refracts to an angle of (29.5+B)^o in the dispersive material. If the index of refraction for green light is 7.50% larger than the index for red light, what is the angle of refraction for the green light in the dispersive material? Give your answer in degrees and with 3 significant figures.

A= 2

B= 2

Answer 1

From Snell's law,

n1 sin(i) = n2 sin(r)

1 sin(44.5) = n2 sin(31.5)

n2 = 1.34

n = 1.34 (1 + 0.075) = 1.44

Angle of refraction,

1 x sin(44.5) = 1.44 sin(theta)

Theta = 29.1°

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