Question

In this problem, you will be creating a MATLAB file that will be able to implement the quadratic formula on any values inputted by the user for variables a, b, and c. Before displaying the solutions, you will display to the user the values they inputted into the program for a, b, and c. An example is shown in Figure 1.

???????????? = ? 2 − 4?c

Along with displaying the resulting solutions from using the quadratic formula, you will also calculate the discriminant and use it to display the type of solution/s that will result if you were to use the quadratic formula. An example is shown in Figure 2. The program must also continue to run until the user has given some indication of wanting to stop the program from running (Use a while loop).

Answer 1

%since images were not provided, program works as shown in the image below.

%attach images if you want it a different way

fprintf('Enter variables a,b,c:(input 0 in all three variables to quit).\n')%ask for input
a=input('a: ');%take user input for 3 variables a b and c
b=input('b: ');
c=input('c: ');
while(a~=0 && b~=0 && c~=0)%loop will run as long as all 3 values are not 0
    fprintf('You entered:\na: %.2f\nb: %.2f\nc: %.2f\n',a,b,c)%values entered by users shown to them
    Discriminant = b*b-4*a*c;%discriminant calculated
    if Discriminant > 0%making decisions based on value of D
        fprintf('The equation has 2 different real solutions!\n')
        fprintf('Solution 1: %.2f\n',(-b+sqrt(Discriminant))/(2*a))
        fprintf('Solution 2: %.2f\n',(-b-sqrt(Discriminant))/(2*a))
    elseif Discriminant < 0
        fprintf('The equation has no real solutions!\n')
    elseif Discriminant == 0
        fprintf('The equation has 1 real solution!\n')
        fprintf('Solution: %.2f\n',(-b/(2*a)))
    end
    %ask for variables again until exit condition is satisfied
    fprintf('Enter variables a,b,c:(input 0 in all three variables to quit).\n')
    a=input('a: ');
    b=input('b: ');
    c=input('c: ');
end