1. Consider the following unbalanced redox reaction:
ClO4−(aq) + I−(aq) →
Cl−(aq) + HIO(aq)
(a) Balance the corresponding half reactions in acidic
conditions using the lowest possible whole number
coefficients.
(Enter coefficients for one and zero. Blanks will be marked
incorrect.)
ClO4−(aq) + H2O(l) + OH−(aq) + H+(aq) + e− → Cl−(aq) + H2O(l) + OH−(aq) + H+(aq) + e−
| Tries 0/3 |
I−(aq) + H2O(l)
+ OH−(aq) + H+(aq)
+ e− → HIO(aq)
+ H2O(l) + OH−(aq)
+ H+(aq) + e−
| Tries 0/3 |
(b) Using the results from part (a), balance the full reaction
in acidic conditions with the lowest possible
whole number coefficients.
(Enter coefficients for one and zero. Blanks will be marked
incorrect.)
ClO4−(aq) + I−(aq) + H2O(l) + OH−(aq) + H+(aq) → Cl−(aq) + HIO(aq) + H2O(l) + OH−(aq) + H+(aq)
| Tries 0/3 |
2. Consider the following unbalanced redox reaction:
NO(g) + BrO3−(aq) →
NO2−(aq) + Br−(aq)
(a) Balance the corresponding half reactions in acidic
conditions using the lowest possible whole number
coefficients.
(Enter coefficients for one and zero. Blanks will be marked
incorrect.)
NO(g) + H2O(l)
+ OH−(aq) + H+(aq)
+ e−
→ NO2−(aq)
+ H2O(l) + OH−(aq)
+ H+(aq) + e−
| Tries 0/3 |
BrO3−(aq) + H2O(l)
+ OH−(aq) + H+(aq)
+ e− → Br−(aq)
+ H2O(l) + OH−(aq)
+ H+(aq) + e−
| Tries 0/3 |
(b) Using the results from part (a), balance the full reaction
in acidic conditions with the lowest possible
whole number coefficients.
(Enter coefficients for one and zero. Blanks will be marked
incorrect.)
NO(g) + BrO3−(aq) + H2O(l) + OH−(aq) + H+(aq) → NO2−(aq) + Br−(aq) + H2O(l) + OH−(aq) + H+(aq)
| Tries 0/3 |
(c) Using the results from part (b), balance the full reaction
in basic conditions with the lowest possible whole
number coefficients.
(Enter coefficients for one and zero. Blanks will be marked
incorrect.)
NO(g) + BrO3−(aq) + H2O(l) + OH−(aq) + H+(aq) → NO2−(aq) + Br−(aq) + H2O(l) + OH−(aq) + H+(aq)
1. Consider the following unbalanced redox reaction: ClO4−(aq) + I−(aq) → Cl−(aq) + HIO(aq) (a) Balance...
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Balance the redox reactions: basic: ClO-(aq)+Cr(OH)4-(aq)----> CrO42-(aq)+Cl-(aq) MnO4-(aq)+Br-(aq)--> MnO2(s)+BrO3-(aq) NO2-(aq)+Al(s)--->NH3(g)+AlO2- Aidic: ClO4-(aq)+Cr(OH)4---->ClO3-(aq)+Cl2(g)
In acidic solution, bromate ion can be used to react with a number of metal ions. One such reaction is: BrO3−(aq)+Sn2+(aq)→Br−(aq)+Sn4+(aq). Since this reaction takes place in acidic solution, H2O(l) and H+(aq) will be involved in the reaction. Places for these species are indicated by the blanks in the following restatement of the equation:BrO3−(aq)+Sn2+(aq)+−→Br−(aq)+Sn4+(aq)+ −−−AWhat are the coefficients of the six species in the balanced equation above? Remember to include coefficients for H2O(l) and H+(aq) in the appropriate blanks. B)What are...
In addition to mass balance, oxidation-reduction reactions must be balanced such that the number of electrons lost in the oxidation equals the number of electrons gained in the reduction. This balancing can be done by two methods: the half-reaction method or the oxidation number method. The half-reaction method balances the electrons lost in the oxidation half-reaction with the electrons gained in the reduction half-reaction. In either method H2O(l), OH−(aq), and H+(aq) may be added to complete the mass balance. Which...