Question

If one wished to obtain 0.15 moles of glacial acetic acid, how many milliliters of glacial acetic acid should be obtained? Enter only the number with two significant figures.

Answer 1

Answer -

Moles of Glacial Acetic Acid = 0.15 mol

Molar Mass of Glacial Acetic Acid = 60.052 g/mol

Volume of Glacial Acetic Acid required in mL = ?

We know that,

Moles = Mass / Molar Mass

So, Mass = Moles * Molar Mass

Mass of Glacial Acetic Acid required = 0.15 mol * 60.052 g/mol

Mass of Glacial Acetic Acid required = 9.0078 g

Also,

Density = mass / Volume

Volume = Mass/Density

Volume of Glacial Acetic Acid = 9.0078 g / 1.05 g/cm³

Volume of Glacial Acetic Acid = 8.578 cm³

Now,

1 cm³ = 1 mL

So, 8.578 cm³ = 8.578 mL

Now, Round off 8.578 to 2 significant figures

8.578 = 8.6 (in 2 significant figures)

So, Volume of Glacial Acetic Acid should be obained is 8.6 mL [ANSWER]