Homework Answers
8.0 % w/v
It means 100 mL solution contains 8.0 g KOH
8.0 g KOH required = 100 mL
23 g KOH required = 100×23/8.0 = 290 mL
2)mole =23/56
=0.411 mol
Volume =0.411/0.24
= 1700 mL
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