Question

part B : how many milliliters of 0.19 M solution could you prepare?

<Chapter 9 Problem 6 Bot 14 If you had only 31 g of KOH remaining in a bottle, how many milliers of 100 %(w/v) solution could you prepare? Express your answer using two significant figures. V = 310 mL Previous Awers Correct Part B How many misters of 0.19 M solution could you prepare? Express your answer using two significant figures % AXO RO? V. 2.0 Submit Previous Answers Request Answer

Answer 1

B)

Molar mass of KOH,

MM = 1*MM(K) + 1*MM(O) + 1*MM(H)

= 1*39.1 + 1*16.0 + 1*1.008

= 56.108 g/mol

mass(KOH)= 31 g

use:

number of mol of KOH,

n = mass of KOH/molar mass of KOH

=(31 g)/(56.11 g/mol)

= 0.5525 mol

use:

M = number of mol / volume in L

0.19 = 0.5525/ volume in L

volume = 2.91 L

volume = 2910 mL

Answer: 2910 mL