A cross is made between a pea plant with round, yellow seeds (WwGg) and one with...
A cross is made between a pea plant with round, yellow seeds
(WwGg) and one with wrinkled, green seeds (wwgg). The
progeny that resulted had the following traits:
round, green: 82
round, yellow: 18
wrinkled, green: 10
wrinkled, yellow: 90
1. Which alleles were on which chromosome in the doubly
heterozygous parent?
2. What is the distance in cM between these two genes?
Homework Answers
Parents are round, yellow and wrinkled green
= WwGg. X. wwgg
Progeny are:
round, green: 82 Wwgg
round, yellow: 18 WwGg
wrinkled, green: 10 wwgg
wrinkled, yellow: 90 wwGg
The genes we got are in trans combination because we have got less parental and more of recombinants.
Parental types : round yellow 18
and wrinkled green 10.
Recombinants: round green 82
Wrinkled yellow 90
Total plants: 200
So the gene round and green are on one chromosome and wrinkled yellow are on another chromosome.
That means the parental one we got above are actually due to recombination in trans combination.
Recombination frequency = 18+10/200= 28/200
= 14%.
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