A fully charged defibrillator contains 1.24 kJ of energy stored in a 1.06x10-4 F capacitor. In...

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A fully charged defibrillator contains 1.24 kJ of energy stored in a 1.06x10-4 F capacitor. In...

A fully charged defibrillator contains 1.24 kJ of energy stored in a 1.06x10^-4 F capacitor. In a discharge through the patient, 588 J of electrical energy are delivered in 3.12 ms. Find the voltage (i.e. potential difference) needed to store this energy in the unit.

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Answer 1

Answer #1

as we know

U = 0.5 CV^2

1.24* 10^3 = 0.5* 1.06* 10^-4* V^2

V = 4836.96 V

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Answer 2

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