Question

A particle is undergoing simple harmonic motion with an equlibirum position of x=0 m.
At t=0 s, the position, velocity, and acceleration are given as:

x =0.454 m
v=0.166 m/s
a=−0.34 m/s2

a) What is the angular frequency of the particle?
ω = rad/s

b) What is the amplitude of the particle?
A = m

c) What is the phase constant of the particle?
ϕ0 = rad

d) What is the particle's position at t=11.3 s?
x = m

e) What is the particle's velocity at t=11.3 s?
v = m/s

Answer 1

Hope this helps...