By serial dilution of the stock with 0.05 M H2SO4, prepare 100 mL each of five standard quinine solutions: 0.01, 0.05, 0.10, 0.50 and 1.00 ppm.
By serial dilution of the stock with 0.05 M H2SO4, prepare 100 mL each of five...
Prepare a series of 50 mL quinine standard solutions (10, 1.0, 0.10, 0.010, 0.0010μg/mL) by serial dilutionfrom the 100 μg/mL stock solution using0.05 M H2SO4as the diluent.
Five standard solutions of HBr are prepared by serial dilution in which, at each stage, 10.00 mL are diluted to 160.00 mL. Given that the concentration of the most dilute solution is 2.62 × 10−6 M, determine the concentration of the original HBr stock solution.
A 4.112-g tablet, containing quinine was dissolved in 0.10 M HCl to give 500 mL. Dilution of a 10.0-mL aliquot to 100 mL yielded a reading for fluorescence intensity (at 347.5 nm) of 320 on an arbitrary scale. A second 10.0-mL aliquot was mixed with 10.0 mL of 100-ppm quinine solution before dilution to 100 mL. The fluorescence intensity of this solution was 433. Calculate the percentage of quinine in the tablet.
Provided materials 0.01 to 0.05 M stock solutions of red and yellow dyes Dyo [stock] 0.0319 M V to mix red V of stock 100 ml 1.00 ml 264 mL yellow 0.0196 M 253 mL Experimental Procedure Dilute stock solutions by adding 1.00 mL of stock to sufficient distilled water to provide a total volume of 1.00 L 1.00 ml aliquots of stock solutions of red (0.0319 M) and yellow (0.0196 M) dyes are separately diluted with distilled water to...
1. 100 ml of 0.05 M H2S + 50ml of 0.1 M NaOH 2. 200 ml of 0.1 M Na2CO3 + 100 ml of 0,365% HCl 3. 50ml of 0.1M Na3PO4 + 100ml of 0.05 M H2SO4 4. 80 ml of 0.01M HNO2 + 20ml of 0.05 M HNO3 5. 20 ml of 0.05 M H2C2O4 + 200 ml of 0.01 M KOH 6. 100 ml of 0.05 M H2S + 100 ml of 0.1 M NaOH 7. 50 ml...
In lab you carried out a serial dilution and calculated the concentration of each solution. Starting with a 2.05 M HCl stock solution, three standard solutions are prepared by sequentially diluting 5.00 mL of each solution to 150.0 mL. What is the concentration of the final solution? 0.0683 M 2.28 times 10^-3 M 9.11 times 10^-6 M 7.59 times 10^-5 M 2.53 times 10^-6 M
Use stock solution of 0.5 M CuSO4 to make up the following solutions by serial dilution to a final volume of 1 ml: 50mM, 5mM, 0.5mM, and 0.05mM Please show 'how many DI water 0.5M CuSO4 needed to be used?'
1. Calculate the concentrations of each of your serial dilution solutions. Report the temperature of the “room temperature” deionized water Show the complete calculations (with appropriate units and significant figures) for the first solution as a sample and the complete Table 1 (below) with the results for all of the solutions. Solution Concentration (M) of crystal violet Absorbance at 590 nm Blank 0.00 0.000 Stock solution 1.00 x 10-5 0.851 Solution 1 0.411 Solution 2 0.203 Solution 3 0.097 Solution...
Bacteria #2 is a Bacteria #3 is a III. Calculation: (1) Serial dilution: (3 pts/each) 1. 0.2 mL of sample is added to 0.8 mL of diluent, what is the Dilution? 2. 0.01 mL of sample is added to 0.99 mL of diluent, what is the Dilution? :100 mL 0.2 mL of a sample was added to 0.8 mL of a diluent. Then, 0.1 mL of this first dilution was added to 0.4 mL of a diluent. What is the...
2. 200 ml of 0.1 M Na2CO3 + 100 ml of 0,365% HCl 3. 50ml of 0.1M Na3PO4 + 100ml of 0.05 M H2SO4 4. 80 ml of 0.01M HNO2 + 20ml of 0.05 M HNO3 5. 20 ml of 0.05 M H2C2O4 + 200 ml of 0.01 M KOH 6. 100 ml of 0.05 M H2S + 100 ml of 0.1 M NaOH How to find pH of solutions