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In horses, black coat is dominant over chestnut and trotting is dominant over pacer. If BbTt...

In horses, black coat is dominant over chestnut and trotting is dominant over pacer. If BbTt was crossed with BbTt,

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all of the offspring would show the dominant trait for color and the recessive trait for gait.

none of the offspring could have the recessive trait for either.

all of the offspring would show the recessive trait for color and the dominant trait for gait.

the expected phenotypic ratio would be 9:3:3:1 dominant, dominant; dominant, recessive; recessive, dominant; recessive, recessive.

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Answer #1

Black coat = BB, Bb

Chestnut = bb

Trotter = TT, Tt

Pacer = tt

BbTt × BbTt

Gametes BT Bt bT bt
BT BBTT black trotter BBTt black trotter BbTT black trotter BbTt black trotter
Bt BBTt black trotter BBtt black pacer BbTt black trotter Bbtt black pacer
bT BbTT black trotter BbTt black trotter bbTT chestnut trotter bbTt chestnut trotter
bt BbTt black trotter Bbtt black pacer bbTt chestnut trotter bbtt chestnut pacer

9 = black trotter

3 = black pacer

3 = chestnut trotter

1 = chestnut pacer

Correct option -

the expected phenotypic ratio would be 9:3:3:1 dominant, dominant; dominant, recessive; recessive, dominant; recessive, recessive

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