1. For the decomposition of NOBr given by
2NOBr(g)⇌ 2NO(s)+Br2(g)
If the equilibrium concentrations of these three chemicals are 0.46
M , 0.10 M, and 0.30M calculate
a) the value of Kc
b) the value of Kp
c) the value of Kc if all given concentrations are doubled
2. For the reaction;
H2(g) + Br2 ⇌ 2HBr (g)
If I start with 0.10 M Hydrogen and 0.20 M bromine what are the
equilibrium concentrations of each if Kc = 62.5?
3. What is the pH of a 0.75M acetic acid solution if Kc = 1.8 x 10-6 ?
1. For the decomposition of NOBr given by 2NOBr(g)⇌ 2NO(s)+Br2(g) If the equilibrium concentrations of these...
2NOBr(g) - 2NO (g) + Br2 (g) Reached equilibrium when the concentrations were: [NOBr] = 0.10 M, [NO] = 0.010 M, and [Br2] = 0.0050 M . What Is the equilibrium constant for this reaction
Consider the following equilibrium: 2NOBr(g) 2NO(g) + Br2(g) An equilibrium mixture is 0.197 M NOBr, 0.333 M NO, and 0.175 M Br2. a) What is the value of Kc at the temperature of the above concentrations? Kc = .5 Correct: Your answer is correct. M b) How many moles/liter of NOBr must be added to the above equilibrium mixture to produce an equilibrium mixture that is 0.381 M Br2? .5587 Incorrect: Your answer is incorrect. mol/L NOBr must be added...
2NO(g) + Br2(g) = 2NOBr(g) Experiment [NO-] (M) [Br2] (M) Initial Rate (M s-1) 1 0.10 0.20 24 2 0.25 0.20 150 3 0.10 0.50 60 4 0.35 0.50 735 1.) Determine the rate law equation for the reaction. 2.) What is the overall order of the reaction? 3.) What are the value and the units of the rate constant, k? 4.) Write the expression to show how is the rate of disappearance of bromine, Br2, related to the rate...
The equilibrium constant for the reaction: 2NO(g) + Br2(g) <----> 2NOBr(g) is Kc = 1.3x10^-2 at 1,000 Ka.) At this temperature, does the equilibrium favor the product or reactants?b.) Calculate Kc for 2NOBr <----> 2NO + Br2c.) Calculate Kc for NOBr <----> NO + 1/2Br2
Consider the following reaction: 2NOBr(g) 2NO(g) + Br2(g) If 0.193 moles of NOBr, 0.210 moles of NO, and 0.293 moles of Br2 are at equilibrium in a 12.0 L container at 413 K, the value of the equilibrium constant, Kp, is .
2NOBr(g) ⇆ 2NO(g) + Br2(g) If nitrosyl bromide, NOBr, is 25.48 percent dissociated at 25°C and the total pressure is 0.325 atm, calculate KP and Kc for the dissociation at this temperature.
2NOBr(g)(double arrow)2NO(g) + Br2(g) If 0.382 moles of NOBr(g), 0.517 moles of NO, and 0.579 moles of Br2 are at equilibrium in a 17.5L container at 522 K, the value of the equilibrium constant, Kc, is
Be sure to answer all parts. Consider the equilibrium 2NOBr(g) ⇆ 2NO(g) + Br2(g) If nitrosyl bromide, NOBr, is 21.66 percent dissociated at 25°C and the total pressure is 0.350 atm, calculate KP and Kc for the dissociation at this temperature.
What is the equilibrium pressure At 373 K, Kp=0.416 for the equilibrium 2NOBr(g)?2NO(g)+Br2(g) If the pressures of NOBr(g) and NO(g) are equal, what is the equilibrium pressure of Br2(g)?
Consider the gas-phase reaction between nitric oxide and bromine at 273 ∘C 2NO(g)+Br2(g)→2NOBr(g). The following data for the initial rate of appearance of NOBr were obtained: Experiment [NO](M) [Br2](M) Initial Rate of Appearance of NOBr(M/s) 1 0.10 0.20 24 2 0.25 0.20 150 3 0.10 0.50 60 4 0.35 0.50 735 What is the rate of disappearance of Br2 when [NO]= 8.1×10−2 M and [Br2]= 0.22 M ? Express your answer using two significant figures.